m^2=0.0196

Solution for m^2=0.0196 equation:

m^2=0.0196

We move all terms to the left:

m^2-(0.0196)=0

We add all the numbers together, and all the variables

m^2-0.0196=0

a = 1; b = 0; c = -0.0196;
Δ = b2-4ac
Δ = 02-4·1·(-0.0196)
Δ = 0.0784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0784}}{2*1}=\frac{0-\sqrt{0.0784}}{2}
=-\frac{\sqrt{}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0784}}{2*1}=\frac{0+\sqrt{0.0784}}{2}
=\frac{\sqrt{}}{2}
$